#include <iostream> using namespace std; int main() { int T,i,j,N,K; cin >> T; int n[T],x; for(i=1; i<=T; i++) { cin >> N >> K; for(int j=1; j<=N; j++) { cin >> x; n[i]+=x/K; x=0; }N=0;K=0; } for(i=1; i<=T; i++) cout << n[i] << endl; return 0; }
question is "Your program will be tested on one or more test cases.The first line of the input will be a single integer T, the number of test cases (1 ≤ T ≤ 100). Followed by the test cases, each test case is on two lines. The first line of each test case contains two integers N, the number of different candies (1 ≤ N ≤ 100), and K, the minimum number of candies which will make a kid happy as described above (1 ≤ K ≤ 100). The second line of each test case contains N integers, separated by a single space, which are the available number of candies of each type. There will be at least 1 candy and at most 100 candies of each type."
sample input: 2 3 2 4 5 7 3 8 4 5 7 sample output: 7 0 when the i tried the above code the answer that i got like: input:2 3 2 5 6 8 2 2 9 1 output: 9 880625041
When i tried to run the code i was getting the 2nd output as garbage value. Can anyone tell me the fault in that code
Problems Reply
Here is the problem:
n[i]+=x/K;
this is equivalent to n[i]=n[i]+x/K;
So it uses a prior value of n[i]
. However, you haven't set any prior value to elements of the array n
. So, initialise the array to 0
first.
for(i=0;i<T;i++)
n[i] = 0;
Also, in this code:
for(int j=1; j<=N; j++)
are you sure that N
will always be less than T
, the size of array? (take care of 0based indexing as well).
 Arrays in C and C++ are zerobased. Run your loops from 0 to N  1 and T  1.

You don't initialise your array values before using them. Formally your program behaviour is undefined. (I think you mean
n[i]=
rather thann[i]+=
.) 
Variable length arrays like
int n[T]
are compiler extensions. Do bear this in mind as it could affect portability.