Unexpected output of scansets in C

as expected this prog. should accept a number until it encounters a 4 but it gives some garbage value. why?

int main(void) { int a; printf("Enter a number: "); scanf("%[^4]d", &a); printf("You entered: %d\n", a); return 0; }

-------------Problems Reply------------

As far as I know scansets are meant to be used with strings (which makes the d not act as an integer placeholder specification). One way to write it is to read the input into a string and then parse it:

int main(void)
{
int a;
char b[255];
printf("Enter a number: ");
scanf("%254[^4]", &b);

a = atoi(b);
printf("You entered: %d\n", a);

return 0;
}

I'm keeping the modified code to a minimum, you'd definitely need some extra checks for input sanity.

To clarify: The 254 prefix limits the amount of data that scanf will capture, so as to not exceed the size of the buffer (strings are terminated with an extra null character, so the read length must be smaller than the actual size)1.

The scanset working with only characters.

Here is my sample code. (but, I don't know what you really want.)

#include <stdio.h>
int main(void) {
char buffer[128];
printf("Enter a number: ");
scanf("%[^4]s", buffer);

printf("You entered: %s\n", buffer);

return 0;
}

The result is,

Enter a number: 12345678
You entered: 123

Additionally, if you want integer value, use atoi().

Category:c# Views:2 Time:2018-07-08
Tags: set

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