# Split number in randomly-sized portions in Python

I have `x = 10` and `y = 100`.

Can I distribute `y` elements in randomly-sized portions among `x` 'element holders'?

I want to create `x` categories each with a random number of items; however, the number of items created should be exactly `y`.

I guess it's something like

`# number of categories and items x = 10, y = 100 # keep track of how many items we have left to add y_left = y # create all categories for i in range(x): # create category # find number of items in this category num_items_in_category = random.randint(1, y_left) # create items for j in range(num_items_in_category): # create item # set new number of items left to add y_left -= num_items_in_category `

Using the functions from this answer you can generate a list of x random numbers that sum to y.

Iterate over the items of this list and make that many random choices (with removal) from a population of elements for each holder.

Or by example:

`# requires RandIntVec() & RandFloats() from linked answer`

``` # whatever population you are choosing from, example letter population = list('qwertyuiopasdfghjklzxcvbnmQWERTYUIOPASDFGHJKLZXCVBNM1234567890') # sizes (whatever you want) num_of_holders = 7 total_elements = len(population) # empty holder to put results in element_holder = [[] for _ in xrange(num_of_holders)] # distribute total_elements elements in randomly-sized portions among num_of_holders 'element holders' random_portions_in_holder = RandIntVec(num_of_holders, total_elements, Distribution=RandFloats(num_of_holders)) # assign each portion of elements to each 'holder' for h, portion in enumerate(random_portions_in_holder): for p in range(portion): index = random.randrange( len(population) ) element_holder[h].append(population.pop(index)) # display print 'Randomly-portioned elements' for h in element_holder: print h ```

```# verify print '\nMatch desired result?' print 'total_elements :', total_elements print 'elements in holders :', sum([len(h) for h in element_holder]) print 'match :', total_elements == sum([len(h) for h in element_holder]) ```

output

```Randomly-portioned elements ['M', 'N', 'f', 'V', 'v', 'h', 'i', 'H', '6', '5', 'j', '7', 'r'] ['u', 'Z', 'C', 'I', 's', 'm', 'g', 'p', 'q', 'a', 'O', 'T', 'L'] ['K', 'E', 'P', 'U'] ['Y', 'D', 'A', 'l', 'J', 'R', 'b', 'c', 'z', 'F'] ['0', '1', 'o', 'X', 'G', '4', 'W', '3', '2'] ['d', 'Q'] ['e', 'y', 'B', '8', 'x', 'k', 'w', 't', 'S', 'n', '9']```

``` ```

```Match desired result? total_elements : 62 elements in holders : 62 match : True ```

P.S. I had some indentation errors when I copied the linked functions, you may need to correct them. The code under `elif Distribution.lower() == 'normal':` needs to by un-indented by 1 level. I submitted an edited version (ending approval), so depending on when you copy, you may or may not need to edit.

This isn't actually too difficult. Let's create our containers:

`import random`

``` num_containers = 10 num_objects = 100 containers = [[] for _ in range(num_containers)] objects = (some_object() for _ in range(num_objects)) # we don't need a list of these, just have to iterate over it, so this is a genexp ```

```for object in objects: random.choice(containers).append(object) ```

Category:python Views:1 Time:2018-04-15

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