Keep multi-character delimiter

I have a string

$string = "hi!n!my!n!name!n!is!n!bob";

I want to split it by the '!n!' I've tried something like:

$splitstring = preg_split("!n!", $string,-1, PREG_SPLIT_DELIM_CAPTURE);

but it removes all instances of 'n' instead of !n! so if i print_r the array, it'll look something like:

Array( [0]=>hi! [1]=>!my! [2]=>! [3]=>!ame! [4]=>!is! [5]=>!bob )

it would split every occurrence of 'n'. not !n! (a 3 character delimiter) like I wanted.

Does anyone know how to solve this? Thanks in advance

-------------Problems Reply------------

You need delimiters (e.g. /) in your regular expression:

$splitstring = preg_split("/!n!/", $string,-1, PREG_SPLIT_DELIM_CAPTURE);

Okay, first of all thanks for all your replies. using / worked but it removed all of the delimiters (!n!). I suspected that PREG_SPLIT_DELIM_CAPTURE wasn't working. So, I found this. The fix was something like:

$splitstring = preg_split("/(!n!)/", $string,-1, PREG_SPLIT_DELIM_CAPTURE);

putting the brackets around the delimiter outputted:


Hope this helps

You could just use explode:

$parts = explode('!n!', $string);

To reproduce the string you started with you can do this:

$string = implode('!n!', $parts);

Finally, if you're looking to keep the delimeter(s) you can always add them back in. It's not clear whether you want them on the start or end of each entity (as your starting string uses them purely as a separator). You could do that like so:

foreach ($parts as &$part)
$part = '!n!'.$part.'!n!';

Category:php Views:6 Time:2019-03-06
Tags: php

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